Sagot:
Paliwanag:
Meron kami
Pagbabahagi ng
kaya nga
Sagot:
Paliwanag:
Una, inilalapat namin ang tambalang anggulo formula sa
Mayroon na kami ngayong:
Mula noon
Paggawa
Samakatuwid,
Ang
Paano mo kalkulahin ang kasalanan (2sin ^ -1 (10x))?
"sinuman" (10x)) = 20xsqrt (1-100x ^ 2) "Let" y = sin (2sin ^ (- 1) (10x) ) => Sin (theta) = 10x => y = sin (2theta) = 2sinthetacostheta Tandaan na: "" cos ^ 2theta = 1-sin ^ 2theta => costheta = sqrt (1-sin ^ 2theta) => y = 2sinthetasqrt (1-sin ^ 2theta) => y = 2 * (10x) sqrt (1- (10x) ^ 2) = kulay (asul) (20xsqrt (1-100x ^ 2))
Katunayan: - kasalanan (7 theta) + kasalanan (5 theta) / kasalanan (7 theta) -in (5 theta) =?
(sin7x + sin5x) / (sin7x-sin5x) = tan6x * cotx rarr (sin7x + sin5x) / (sin7x-sin5x) = (2sin ((7x + 5x) / 2) ) / (2sin ((7x-5x) / 2) * cos ((7x + 5x) / 2) = (sin6x * cosx) / (sinx * cos6x) = (tan6x) / tanx = tan6x * cottx
Patunayan na ang Cot 4x (kasalanan 5 x + kasalanan 3 x) = Cot x (kasalanan 5 x - kasalanan 3 x)?
# sin isang + sin b = 2 sin ((a + b) / 2) cos ((ab) / 2) sin isang - sin b = 2 sin ((ab) / 2) cos ((a + b) / 2 ) Kanang bahagi: cot x (sin 5x - sin 3x) = cot x cdot 2 sin ((5x-3x) / 2) cos ((5x + 3x) / 2) = cos x / sin x cdot 2 sin x cos 4x = 2 cos x cos 4x Kaliwa: cot (4x) (kasalanan 5x + kasalanan 3x) = cot (4x) cdot 2 kasalanan ((5x + 3x) / 2) cos ((5x-3x) / 2) = {cos 4x} / {sin 4x} cdot 2 sin 4x cos x = 2 cos x cos 4 x They are equal quad sqrt #