Paano mo kalkulahin ang kasalanan (2sin ^ -1 (10x))?

Sagot:

#sin (2sin ^ (- 1) (10x)) = 20xsqrt (1-100x ^ 2) #

Paliwanag:

# "Let" y = sin (2sin ^ (- 1) (10x)) #

Ngayon, hayaan # "" theta = sin ^ (- 1) (10x) "" => sin (theta) = 10x #

# => y = sin (2theta) = 2sinthetacostheta #

Tandaan na: # "" cos ^ 2theta = 1-sin ^ 2theta => costheta = sqrt (1-sin ^ 2theta) #

# => y = 2sinthetasqrt (1-sin ^ 2theta) #

# => y = 2 * (10x) sqrt (1- (10x) ^ 2) = kulay (asul) (20xsqrt (1-100x ^ 2)) #