Sagot:
Upang i-graph
Paliwanag:
Ang ibinigay na equation
Itakda
Mayroon kaming y-intercept sa
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Itakda ngayon
Mayroon kaming x-intercept sa
Iba pang mga puntos ay
Dahil ang graph ng
Kung tanx = -1/3, cos> 0, kung paano mo nahanap ang tan2x?
Tan 2x = (2tanx) / (1 - kayumanggi ^ 2x) Ang pagkakakilanlan na ito ay madaling gamitin, baka gusto mong kabisaduhin ito. = (2 (-1/3)) / (1 - 1/9) = (- 2/3) / (8/9) = -2 / 3 (9/8) = -3/4
Patunayan na ang (Sinx + Sin2x + Sin3x) / (cosx + cos2x + cos3x) = tan2x
(3x-x) / 2) + sin2x) / (2cos ((3x + (sinx + sin2x + sin3x) / (cosx + cos2x + cos3x) (2x2x * cosx + cos2x) = (sin2xcancel ((1 + 2cosx))) / (cos2xcancel (( 1 + 2cosx))) = tan2x = RHS
Lutasin ang 1 / (tan2x-tanx) -1 / (cot2x-cotx) = 1?
1 / (tan2x-tanx) -1 / (cot2x-cotx) = 1 => 1 / (tan2x-tanx) -1 / (1 / (tan2x) -1 / tanx) = 1 => 1 / (tan2x- tanx ) 1 / (1 / (tanx) -1 / (tan2x)) = 1 => 1 / (tan2x-tanx) + (tanxtan2x) / (tan2x-tanx) = 1 => (1 + tanxtan2x) / (tan2x -tanx) = 1 => 1 / tan (2x-x) = 1 => tan (x) = 1 = tan (pi / 4) => x = npi + pi / 4