Ano ang polar form ng y = x ^ 2-x / y ^ 2 + xy ^ 2?

Sagot:

# r ^ 2 (rcos ^ 2theta + rcosthetasin ^ 2theta-sintheta) = cotthetacsctheta #

Paliwanag:

Para sa ganitong paraan gagamitin namin ang:

# x = rcostheta #

# y = rsinthetra #

# rsintheta = (rcostheta) ^ 2- (rcostheta) / (rsintheta) ^ 2 + r ^ 2costhetasin ^ 2theta #

# rsintheta = r ^ 2cos ^ 2theta- (cotthetacsctheta) / r + r ^ 2costhetasin ^ 2theta #

# r ^ 2sintheta = r ^ 3cos ^ 2theta-cotthetacsctheta + r ^ 3costhetasin ^ 2theta #

# r ^ 3cos ^ 2theta + r ^ 3costhetasin ^ 2theta-r ^ 2sintheta = cotthetacsctheta #

# r ^ 2 (rcos ^ 2theta + rcosthetasin ^ 2theta-sintheta) = cotthetacsctheta #

Ito ay hindi maaaring pinasimple pa at kailangang iwanang bilang isang pahiwatig na equation.