(Sqrt (2) / 2) x (sqrt (3) / 2) - (1/2) x (sqrt (2) / 2) -1)?

(Sqrt (2) / 2) x (sqrt (3) / 2) - (1/2) x (sqrt (2) / 2) -1)?
Anonim

Sagot:

Ngayon mas mabuti pa.

Paliwanag:

# (sqrt2 / 2) (sqrt3 / 2) - (1/2) (sqrt2 / 2) #

# ((sqrt2) (sqrt3)) / 4-sqrt2 / 4 #

# sqrt2 / 4 sqrt3-1 #

Sagot:

Tingnan sa ibaba …

Paliwanag:

#sqrt (2) / 2 * sqrt (3) / 2-1 / 2 * sqrt (2) / 2 = #

# (sqrt (2) * sqrt (3)) / (2 * 2) - (1 * sqrt (2)) / (2 * 2) = #

# (kulay (pula) (sqrt (2)) * sqrt (3)) / kulay (pula) (4) -color (pula) (sqrt (2) / 4) = #

#sqrt (2) / 4 * (sqrt (3) -1) #