Ano ang karaniwang anyo ng y = - (x - 1) (x ^ 2 +6) (x / 3 + 2)?

Ano ang karaniwang anyo ng y = - (x - 1) (x ^ 2 +6) (x / 3 + 2)?
Anonim

Sagot:

# y = -1 / 3x ^ 4-5 / 3x ^ 3-10x + 12 #

Paliwanag:

#y = - (x-1) (x ^ 2 + 6) (x / 3 + 2) #

#y = - (x ^ 3 + 6x-x ^ 2-6) (1/3) (x + 6) #

# y = -1 / 3 (x ^ 3-x ^ 2 + 6x-6) (x + 6) #

# y = -1 / 3 (x ^ 4-x ^ 3 + 6x ^ 2-6x + 6x ^ 3-6x ^ 2 + 36x-36) #

# y = -1 / 3 (x ^ 4 + 5x ^ 3 + 30x-36) #

# y = -1 / 3x ^ 4-5 / 3x ^ 3-10x + 12 #

Na angkop sa karaniwang paraan ng # y = Ax ^ 4 + Bx ^ 3 + Cx ^ 2 + Dx + E #