Paggamit ng Chebyshev Polynomial T_n (x) = cosh (n (arc cosh (x))), x> = 1 at ang kaugnay na pag-uulit T_ (n + 2) (x) = 2xT_ (n + 1) x), sa T_0 (x) = 1 at T_1 (x) = x, paano mo i-porve ang cosh (7 arc cosh (1.5)) = 421.5?

# T_0 (1.5) # o sa madaling sabi, # T_0 = 1 #.

# T_1 = 1.5 #

# T_2 = 2 (1.5) (1.5) T_1-T_0 = 4.5-1 = 3.5 #, gamit #T_n = 2xT_ (n-1) -T_ (n-2), n> = 2 #.

# T_3 = 3 (3.5) -1.5 = 9 #

# T_4 = 3 (9) -3.5 = 23.5 #

# T_5 = 3 (23.5) -9 = 61.5 #

# T_6 = 3 (61.5) -23.5 = 161 #

# T_7 = 3 (161) -61.5 = 421.5 #

Mula sa wiki Chebyshev Polynomials Table,.

# T_7 (x) = 64x ^ 7-112x ^ 5 + 56x ^ 3-7x