Ano ang pamantayang anyo ng y = (x + 3) ^ 3?

Ano ang pamantayang anyo ng y = (x + 3) ^ 3?
Anonim

Sagot:

# x ^ 3 + 9x ^ 2 + 27x + 27 #

Paliwanag:

# "Given" (x + a) (x + b) (x + c) "ang pagpapalawak ay" #

# = x ^ 3 + (a + b + c) x ^ 2 + (ab + bc + ac) x + abc #

# "ngayon" (x + 3) ^ 3 = (x + 3) (x + 3) (x + 3) #

# "may" a = b = c = 3 #

#rArr (x + 3) ^ 3 #

# = x ^ 3 + (3 + 3 + 3) x ^ 2 + (9 + 9 + 9) x + (3xx3xx3xx3) #

# = x ^ 3 + 9x ^ 2 + 27x + 27 #

Sagot:

#color (asul) (y = x ^ 3 + 9x ^ 2 + 27x + 27) #

Paliwanag:

# y = (x + 3) ^ 3 #

#color (puti) (……….) x + 3 #

#color (white) (……) xx x + 3 #

#color (white) (…………) overline (x ^ 2 + 3x) #

#color (puti) (…………..) + 3x + 9 #

#color (white) (………..) overline (x ^ 2 + 6x + 9) #

#color (white) (…….) xx x + 3 #

#color (white) (………….) overline (x ^ 3 + 6x ^ 2 + 9x) #

#color (white) (………………….) 3x ^ 2 + 18x + 27 #

#color (white) (………….) overline (kulay (asul) (x ^ 3 + 9x ^ 2 + 27x + 27) #