Paano mo hahatiin (7-9i) / (- 2-9i) sa trigonometriko form?

Paano mo hahatiin (7-9i) / (- 2-9i) sa trigonometriko form?
Anonim

Sagot:

#sqrt (442) / 17 cos (tan ^ -1 ((- 81) / - 67)) + i * kasalanan (tan ^ -1 ((- 81) / - 67)) # O

#sqrt (442) / 17 cos (50.403791360249 ^ @) + i * sin (50.403791360249 ^ @) #

Paliwanag:

I-convert muna ang Trigonometriko form

# 7-9i = sqrt130 cos (tan ^ -1 ((- 9) / 7)) + ako sin (tan ^ -1 ((- 9) / 7)) #

# -2-9i = sqrt85 cos (tan ^ -1 ((- 9) / - 2)) + i sin (tan ^ -1 ((- 9) / - 2)) #

Paghati-hatiin ay katumbas ng katumbas

# (7-9i) / (- 2-9i) = #

# (sqrt130 / sqrt85) cos (tan ^ -1 ((- 9) / 7) -tan ^ -1 ((- 9) / - 2)) + i sin (tan ^ -1 ((- 9) / 7) -tan ^ -1 ((- 9) / - 2)) #

Tandaan ang formula:

#tan (A-B) = (Tan A-Tan B) / (1 + Tan A * Tan B) #

din

# A-B = Tan ^ -1 (Tan A-Tan B) / (1 + Tan A * Tan B)) #

#sqrt (442) / 17 cos (tan ^ -1 ((- 81) / - 67)) + i * kasalanan (tan ^ -1 ((- 81) / - 67)) #

magandang araw!