Paano mo pinasimple (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5)?

Paano mo pinasimple (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5)?
Anonim

Sagot:

# (3x + 2) / (3x + 1) #

Paliwanag:

Ituro ang mga termino:

# (3x ^ 2 + 14x + 8) / (2x ^ 2 + 7x-4) * (2x ^ 2 + 9x-5) / (3x ^ 2 + 16x + 5) = #

(X + 4)) / ((2x-1) (x + 4)) * ((2x-1) (x + 5)) / ((3x + 1))) #

Kanselahin ang magkatulad na mga terminong matatagpuan sa factorisation:

(X + 4)) / ((2x-1) (x + 4)) * ((2x-1) (x + 5)) / ((3x + 1))) = #

# (3x + 2) / (3x + 1) #