Ano ang x kung ln (x ^ 2) + ln (x ^ 3) + 2 = 0?

Sagot:

# x = root (5) (1 / e ^ 2) #

Paliwanag:

# 1 "" lnx ^ 2 + lnx ^ 3 + 2 = 0 #

Ari-arian: # log_bm + log_bn = log_b (mn) #

# 2 "" "ln (x ^ 2x ^ 3) + 2 = 0 #

# 3 "" ln (x ^ 5) + 2 = 0 #

Ilipat 2 sa kabilang panig.

# 4 "" ln (x ^ 5) = - 2 #

# 5 "" log_e (x ^ 5) = - 2 #

I-convert sa exponential form.

# 6 "" hArre ^ -2 = x ^ 5 #

# "7" "" root (5) (1 / e ^ 2) = root (5) (x ^ 5) #

"" Kulay "(asul) (x = root (5) (1 / e ^ 2)) #