Sagot:
Paliwanag:
Gumamit lamang ng binagong bersyon ng palara o isang talahanayan
Lamang idagdag ang lahat ng ito
Sagot:
# x ^ 4 + 4x ^ 3 + 8x ^ 2 + 8x-5 #
Paliwanag:
Given-
# (x ^ 2 + 2x-1) (x ^ 2 + 2x + 5) #
(x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x 2x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x x xx5) + (2x xx5) - (1xx5) #
# x ^ 4 + 2x ^ 3-x ^ 2 + 2x ^ 3 + 4x ^ 2-2x + 5x ^ 2 + 10x-5 #
# x ^ 4 + 2x ^ 3 + 2x ^ 3-x ^ 2 + 4x ^ 2 + 5x ^ 2-2x + 10x-5 #
# x ^ 4 + 4x ^ 3 + 8x ^ 2 + 8x-5 #
Paano mo paramihin ang 7x ^ 2y (5x ^ 2-3xy + y)?
35x ^ 4y-21x ^ 3y ^ 2 + 7x ^ 2y ^ 2 7x ^ 2y (5x ^ 2-3xy + y) 35x ^ 4y-21x ^ 3y ^ 2 + 7x ^ 2y ^ 2
Paano mo paramihin ang sqrt (x) * (x)?
Sqrtx * x = sqrt (x ^ 3) Alam na sqrtx = x ^ (1/2) at gamit ang mga katangian: x ^ a * x ^ b = x ^ (a + b) (x ^ a) ^ b = ^ (a * b) mayroon kang: sqrtx * x = x ^ (1/2) * x ^ 1 = x ^ (1/2 + 1) = x ^ (3/2) = (x ^ 3) ^ ( 1/2) = sqrt (x ^ 3)
Paano mo paramihin at gawing simple ang frac {x ^ {2} - 3x - 10} {x ^ {2} - 4x - 12} cdot frac {6- x} {x ^ {2} - 25}?
(X + 2) (x-5)) / ((x + 2) (x-6)) * (6-x) / ((x-5 (x + 5)) = ((x + 2) (x-5) (6-x)) / ((x + 2) (x-6) (x-5) kanselahin ((x-5)) (6-x)) / (kanselahin ((x + 2)) (x-6) kanselahin ((x-5)) (x + 5) = (6-x) / ((x-6) (x + 5)) (6-x) = - (x-6) (6-x) / ((x-6) (x + 5) - (x-6) / ((x-6) (x + 5)) = - 1 / (x + 5)