Ano ang hinalaw ng (3 + 2x) ^ (1/2)?

Sagot:

# 1 / ((3 + 2x) ^ (1/2)) #

Paliwanag:

# "iba-iba ang paggamit ng" kulay (bughaw) "tuntunin ng chain" #

# "ibinigay" y = f (g (x)) "pagkatapos" #

# dy / dx = f '(g (x)) xxg' (x) larrcolor (asul) "chain rule" #

# rArrd / dx ((3 + 2x) ^ (1/2)) #

# = 1/2 (3 + 2x) ^ (- 1/2) xxd / dx (3 + 2x) #

# = 1 (3 + 2x) ^ (- 1/2) = 1 / ((3 + 2x) ^ (1/2)) #

Sagot:

# 1 / (sqrt (3 + 2x)) #

Paliwanag:

Kung

#f (x) = (3 + 2x) ^ (1/2) = (sqrt (3 + 2x)) #

(ilapat ang tuntunin ng kadena)

# u = 3 + 2x #

# u '= 2 #

#f (u) = u ^ (1/2) #

#f '(u) = (1/2) (u) ^ (- 1/2) beses u' #

Kaya:

#f '(x) = (1/2) (3 + 2x) ^ (- 1/2) beses 2 #

#f '(x) = (3 + 2x) ^ (- 1/2) #

#f '(x) = (1) / (sqrt (3 + 2x)) #