Tanong # f472a

Tanong # f472a
Anonim

Sagot:

# z = y / (3y / x + 3/2) #

Paliwanag:

Una, gusto mong i-on ang # x #, # y # at # z # mga kapangyarihan sa mga kadahilanan. Upang gawin ito, gamitin ang naperian logarithm:

#color (grey) (Tandaan: ln (a * b) = ln (a) + ln (b) at ln (a ^ b) = bln (a)) #

#ln (2 ^ x) = ln (3 ^ y) = ln ((24sqrt3) ^ z) #

# = xln (2) = yln (3) = zln (24sqrt3) #

Pagkatapos, ihiwalay # z #:

# y = (yln (3)) / (ln (24sqrt3)) = (yln (3)) / (ln (3 * 2 ^ 3) + ln (3 ^ (1/2))) #

# = (yln (3)) / (3ln (2) + ln (3) + ln (3) / 2) #

Palitan #ln (2) # may # y / xln (3) #

# z = (yln (3)) / (3y / xln (3) + ln (3) + ln (3) / 2) #

# = (ycancel (ln (3))) / ((3y / x + 1 + 1/2) kanselahin (ln (3))) = y / (3y / x + 3/2) #