Sagot:
Katunayan sa ibaba
Paliwanag:
Una naming patunayan # 1 + tan ^ 2theta = sec ^ 2theta #:
# sin ^ 2theta + cos ^ 2theta = 1 #
# sin ^ 2theta / cos ^ 2theta + cos ^ 2theta / cos ^ 2theta = 1 / cos ^ 2theta #
# tan ^ 2theta + 1 = (1 / costheta) ^ 2 #
# 1 + tan ^ 2theta = sec ^ 2theta #
Ngayon maaari naming patunayan ang iyong katanungan:
# sec ^ 4theta #
# = (sec ^ 2theta) ^ 2 #
# = (1 + tanaw ^ 2theta) ^ 2 #
# = 1 + 2tan ^ theta + tan ^ 4theta #