Paano mo gawing simple (x ^ 2 - 16) / (2x ^ 2 - 9x + 4) div (2x ^ 2 + 14x + 24) / (4x + 4)?

Paano mo gawing simple (x ^ 2 - 16) / (2x ^ 2 - 9x + 4) div (2x ^ 2 + 14x + 24) / (4x + 4)?
Anonim

Sagot:

# (2 (x + 1)) / ((2x-1) (x + 3)) #

Paliwanag:

Sa pamamagitan ng factoring tandaan na:

# (x ^ 2-16) / (2x ^ 2-9x + 4) ÷ (2x ^ 2 + 14x + 24) / (4x + 4) = #

(x + 4) (x-4)) / ((2x-1) (x-4)) * (4 (x +

Kanselahin tulad ng mga termino:

kanselahin ((x-4))) / ((2x-1) kanselahin ((x-4))) * (kanselahin (4) kulay (asul) (2) (x +1)) / (kanselahin (2) (x + 3) kanselahin ((x + 4))) = #

# (2 (x + 1)) / ((2x-1) (x + 3)) #