Mayroon kaming A (x) = x ^ 2-6x + 4 ang tanong ay factorise A (x) +5?

Mayroon kaming A (x) = x ^ 2-6x + 4 ang tanong ay factorise A (x) +5?
Anonim

Sagot:

#A (x) = (x-3) * (x-3) #

Paliwanag:

Meron kami, #A (x) = x ^ 2-6x + 4 #

Kaya, #color (white) (xxx) A (x) + 5 = (x ^ 2-6x + 4) + 5 #

#rArr A (x) = x ^ 2-6x + 9 #

#rArr A (x) = (x) ^ 2 - 2 * x * 3 + (3) ^ 2 #

#rArr A (x) = (x- 3) ^ 2 #

#rArr A (x) = (x - 3) (x - 3) #

Tandaan na

#color (pula) a ^ 2x ^ 2-bx + c ^ 2 = (sqrt (a ^ 2x ^ 2) -sqrt (c ^ 2)) ^ 2 = (ax-c) ^ 2 Saan #b = 2ac #