Paano mo i-convert (11, -9) sa mga coordinate ng polar?

Sagot:

# (sqrt202, tan ^ -1 (-9/11) + 2pi) o (14.2,5.60 ^ c) #

Paliwanag:

(x, y) -> (r, theta); (r, theta) = (sqrt (x ^ 2 + y ^ 2), tan ^ -1 (y / x)

# r = sqrt (x ^ 2 + y ^ 2) = sqrt (11 ^ 2 + (- 9) ^ 2) = sqrt (121 + 81) = sqrt202 ~~ 14.2 #

# theta = tan ^ -1 (-9/11) #

Gayunpaman, #(11,-9)# ay nasa kuwadrado 4, at sa gayon ay kailangan nating idagdag # 2pi # sa aming sagot.

# theta = tan ^ -1 (-9/11) + 2pi ~~ 5.60 ^ c #

# (sqrt202, tan ^ -1 (-9/11) + 2pi) o (14.2,5.60 ^ c) #