Ano ang cos (sin ^ -1 (0.5))?

Ano ang cos (sin ^ -1 (0.5))?
Anonim

Sagot:

#cos (sin ^ (- 1) (0.5)) = sqrt (3) / 2 #

Paliwanag:

Hayaan #sin ^ (- 1) (0.5) = x # pagkatapos

# rarrsinx = 0.5 #

# rarrcosx = sqrt (1-sin ^ 2x) = sqrt (1-0.5 ^ 2) = sqrt (1- (1/2) ^ 2) = sqrt (3) / 2 #

# rarrx = cos ^ (- 1) (sqrt3 / 2) = sin ^ (- 1) (0.5) #

Ngayon, #rarrcos (sin ^ (- 1) (0.5)) = cos (cos ^ (- 1) (sqrt3 / 2)) = sqrt (3) / 2 #