Paano mo i-convert ang 2y = y ^ 2-x ^ 2 -4x sa isang polar equation?

Sagot:

#r = - ((2sin (theta) + 4cos (theta)) / cos (2theta)) #

Paliwanag:

# 2y = y ^ 2-x ^ 2-4x #

# x = rcos (theta) #

# y = rsin (theta) #

I-plug ang mga halagang ito sa ibinigay na equation

# 2rsin (theta) = r ^ 2sin ^ 2 (theta) -r ^ 2cos ^ 2 (theta) -4rcos (theta) #

# 2rsin (theta) + 4rcos (theta) = - r ^ 2 (cos ^ 2 (theta) - sa ^ 2 (theta)) #

#r (2sin (theta) + 4cos (theta)) = - r ^ 2 (cos (2theta)) #

Ginamit ang pagkakakilanlan #cos (2theta) = cos ^ 2 (theta) -in ^ 2 (theta) #

#r = - ((2sin (theta) + 4cos (theta)) / cos (2theta)) #