Paano mo mahanap ang mga intercepts para sa y = x ^ 2-9x + 20?

Sagot:

Nagtatakda ka # y = 0 # para sa # x # intercepts at # x = 0 # para sa # y # intercepts. Pagkatapos ay malutas mo ang mga equation.

# x = 5 #

# x = 4 #

# y = 20 #

y intercepts

# y = 0 #

# x ^ 2-9x + 20 = 0 #

# Δ = b ^ 2-4ac #

#Δ=(-9)^2-4*1*20=1#

#x_ (1,2) = (- b + -sqrt (Δ)) / (2a) #

#x_ (1,2) = (- (- 9) + - sqrt (1)) / (2 * 1) #

#x_ (1,2) = (9 + -1) / 2 #

# x_1 = 5 # 1st y intercept

# x_2 = 4 # 2nd y intercept

graph {x ^ 2-9x + 20 -6.84, 15.67, -2, 9.27}

x intercepts

# x = 0 #

# y = 0 ^ 2-9 * 0 + 20 #

# y = 20 # 1st (at tanging) x maharang

graph {x ^ 2-9x + 20 -28.64, 29.12, -0.73, 28.17}