Paano mo pinasimple ang sqrt (x-1) + sqrt (2x) = 3?

Sagot:

# rarrx = 2 #

Paliwanag:

#rarrsqrt (x-1) + sqrt (2x) = 3 #

#rarrsqrt (x-1) = 3-sqrt (2x) #

#rarr sqrt (x-1) ^ 2 = 3-sqrt (2x) ^ 2 #

# rarrx-1 = 9-6sqrt (2x) + 2x #

# rarr6sqrt (2x) = x + 10 #

#rarr 6sqrt (2x) ^ 2 = x + 10 ^ 2 #

# rarr36 * (2x) = x ^ 2 + 20x + 100 #

# rarrx ^ 2-52x + 100 = 0 #

# rarrx ^ 2-2 * x * 26 + 26 ^ 2-26 ^ 2 + 100 = 0 #

#rarr (x-26) ^ 2 = 26 ^ 2-100 = 576 #

# rarrx-26 = sqrt (576) = + - 24 #

# rarrx = 26 + 24,26-24 = 50 o 2 #

Paglalagay # x = 50 # sa ibinigay na equation, makuha namin, #rarrsqrt (50-1) + sqrt (2 * 50) = 17 (tinanggihan) #

Paglalagay # x = 2 # sa ibinigay na equation, makuha namin, #rarrsqrt (2-1) + sqrt (2 * 2) = 3 (tinanggap) #

Kaya, ang kinakailangang halaga ng x ay #2.#