Ano ang axis ng simetrya at vertex para sa graph y = -3x ^ 2 + 12x + 4?

Sagot:

aos = 2

vertex = (2,16)

#y = -3x ^ 2 + 12x + 4 #

#f (x) = -3x ^ 2 + 12x + 4 #

Sa anyo # y = ax ^ 2 + bx + c # mayroon kang:

# a = -3 #

# b = 12 #

# c = 4 #

Axis of symmetry (aos) ay: #aos = (- b) / (2a) = (-12) / (2 * -3) = 2 #

Tandaan # y = f (x) #

Ang Vertex ay: # (aos, f (aos)) = (2, f (2)) #:

#f (x) = -3x ^ 2 + 12x + 4 #

#f (2) = -3 (2) ^ 2 + 12 * 2 + 4 = 16 #

kaitaasan #=(2, 16)#

graph {-3x ^ 2 + 12x + 4 -16.71, 23.29, -1.6, 18.4}

Vertex -

#(2,16)#

Axis of symmetry

# x = 2 #

Given -

# y = -3x ^ 2 + 12x + 4 #

Vertex -

#x = (- b) / (2a) = (- 12) / (2xx-3) = (- 12) / (- 6) = 2 #

Sa # x = 2; y = -3 (2 ^ 2) +12 (2) + 4 #

# y = -12 + 24 + 4 = 16 #

#(2,16)#

Axis of symmetry

# x = 2 #