Powers (kung paano 2 ^ (2017/2) = sqrt2 * 2 ^ 1008 gumagana)?

Powers (kung paano 2 ^ (2017/2) = sqrt2 * 2 ^ 1008 gumagana)?
Anonim

Tandaan muna na:

#sqrt (a ^ 3) = sqrt (axxa ^ 2) => asqrta #

# a ^ (x / y) = root y (a ^ x) #

#sqrt (a ^ x) = a ^ (x / 2) #

Alam namin iyan # 2 ^ (2017/2) = sqrt (2 ^ 2017) #

Sa pangalawang at pangatlong panuntunan, alam natin iyan #sqrt (2 ^ 2017) = sqrt (2xx2 ^ 2016) => 2 ^ (2016/2) sqrt2 #

Kapag pinasimple, ito ay nagiging # 2 ^ 1008sqrt2 #