Paano mo naiiba ang f (x) = sqrt (ln (x ^ 2 + 3) gamit ang tuntunin ng kadena.

Paano mo naiiba ang f (x) = sqrt (ln (x ^ 2 + 3) gamit ang tuntunin ng kadena.
Anonim

Sagot:

#f '(x) = (x (ln (x ^ 2 + 3)) ^ (- 1/2)) / (x ^ 2 + 3) = x / ((x ^ 2 + 3) (ln (x ^ 2 + 3)) ^ (1/2)) = x / ((x ^ 2 + 3) sqrt (ln (x ^ 2 + 3))) #

Paliwanag:

Kami ay binibigyan ng:

# y = (ln (x ^ 2 + 3)) ^ (1/2) #

# y '= 1/2 * (ln (x ^ 2 + 3)) ^ (1 / 2-1) * d / dx ln (x ^ 2 + 3) #

#y '= (ln (x ^ 2 + 3)) ^ (- 1/2) / 2 * d / dx ln (x ^ 2 + 3) #

# d / dx ln (x ^ 2 + 3) = (d / dx x ^ 2 + 3) / (x ^ 2 + 3) #

# d / dx x ^ 2 + 3 = 2x #

#y '= (ln (x ^ 2 + 3)) ^ (- 1/2) / 2 * (2x) / (x ^ 2 + 3) = (x (ln (x ^ 2 + 3)) ^ = X / ((x ^ 2 + 3) (ln (x ^ 2 + 3)) ^ (1/2)) = x / ((x ^ 2 +3) sqrt (ln (x ^ 2 + 3))) #