Kung Sin (π / 5 + x) = cos (π / 7 + 2x), kung ano ang x?

Kung Sin (π / 5 + x) = cos (π / 7 + 2x), kung ano ang x?
Anonim

Sagot:

# x = (11pi) / 210 #

Paliwanag:

#rarrsin (pi / 5 + x) = cos (pi / 7 + 2x) #

#rarrcos (pi / 2 (pi / 5 + x)) = cos (pi / 7 + 2x) #

# rarrpi / 2- (pi / 5 + x) = pi / 7 + 2x #

# rarrpi / 2-pi / 5-pi / 7 = 2x + x = 3x #

# rarr3x = (11pi) / 70 #

# rarrx = (11pi) / 210 #