Ano ang kaitaasan ng y = x-2 + (x-3) ^ 2?

Sagot:

Nasa Vertex #(2.5,0.75) #

# y = x-2 + (x-3) ^ 2 o y = x-2 + x ^ 2-6x + 9 # o

# y = x ^ 2-5x + 7 o y = (x ^ 2-5x) + 7 # o

# y = {x ^ 2-5x + (5/2) ^ 2} -25/4 + 7 # o

# y = (x-2.5) ^ 2 + 3/4 o y = {x-2.5} ^ 2 + 0.75 #

Paghahambing sa vertex form ng equation

#y = a (x-h) ^ 2 + k; (h, k) # pagiging tuktok na nakita namin

dito # h = 2.5, k = 0.75:. # Nasa Vertex #(2.5,0.75) #.

graph {(x-2) + (x-3) ^ 2 -10, 10, -5, 5} Ans