Sagot:
#4#
Paliwanag:
# = lim_ {n-> oo} (3 / n ^ 3) sum_ {i = 1} ^ {i = n} i ^ 2 + (3 / n) sum_ {i = n} 1 #
# "(Formula ng Faulhaber)" #
(n / 1) (2n + 1)
# = lim_ {n-> oo} (3 / n ^ 3) n ^ 3/3 + n ^ 2/2 + n / 6 + (3 / n) n #
# = lim_ {n-> oo} 1 + ((3/2)) / n + ((1/2)) / n ^ 2 + 3 #
# = lim_ {n-> oo} 1 + 0 + 0 + 3 #
#= 4#
Sagot:
# 4#.
Paliwanag:
Narito ang isa pa paraan upang malutas ang Problema:
Tandaan na, # int_0 ^ 1f (x) dx = lim_ (n to oo) sum_ (i = 1) ^ n1 / nf (i / n) … (bituin) #.
#: "Ang Reqd Lim. =" Lim_ (n sa oo) sum_ (i = 1) ^ n3 / n {(i / n) ^ 2 + 1} #, # = 3 lim_ (n to oo) sum_ (i = 1) ^ n1 / n {(i / n) ^ 2 + 1} #, # = 3int_0 ^ 1 {(x) ^ 2 + 1} dx ………… dahil, (bituin) #,
# = 3 x ^ 3/3 + x _0 ^ 1 #, # = x ^ 3 + 3x _0 ^ 1 #, # = 1 ^ 3 + 3xx1- (0 ^ 3 + 3xx0) #, #rArr "Ang Reqd Lim. =" 4 #.